AJAX - XMLHttpRequest
The XMLHttpRequest object is used to request data from a server.
Send a Request To a Server
To send a request to a server, we use the open() and send() methods of the XMLHttpRequest object:
xhttp.open("GET", "ajax_info.txt", true);
xhttp.send();
Method
Description
open(method, url, async)
Specifies the type of request
method: the type of request: GET or POST
url: the server (file) location
async: true (asynchronous) or false (synchronous)
send()
Sends the request to the server (used for GET)
send(string)
Sends the request to the server (used for POST)
The url - A File On a Server
The url parameter of the open() method, is an address to a file on a server:
xhttp.open("GET", "ajax_test.asp", true);
The file can be any kind of file, like .txt and
.xml, or server scripting files like .asp and .php (which can perform
actions on the server before sending the response back).
Asynchronous - True or False?
Server requests should be sent asynchronously.
The async parameter of the open()
method should be set to true:
xhttp.open("GET", "ajax_test.asp", true);
By sending asynchronously, the
JavaScript does not have to wait for the server response, but can instead:
execute other scripts while waiting for server response
deal with the response after the response is ready
The default value for the async parameter is async = true.
You can safely remove the third parameter from your code.
Synchronous XMLHttpRequest (async = false) is not recommended because the JavaScript will
stop executing until the server response is ready. If the server is busy or slow, the
application will hang or stop.
GET or POST?
GET is simpler and faster than POST, and can be used in most cases.
However, always use POST requests when:
A cached file is not an option (update a file or database on the server).
Sending a large amount of data to the server (POST has no size limitations).
Sending user input (which can contain unknown characters), POST is more robust and secure than GET.
GET Requests
A simple GET request:
Example
xhttp.open("GET", "demo_get.asp");
xhttp.send();
Try it Yourself »
In the example above, you may get a cached result. To avoid this, add a unique ID to the URL:
Example
xhttp.open("GET", "demo_get.asp?t=" + Math.random());
xhttp.send();
Try it Yourself »
If you want to send information with the GET method, add the information to the URL:
Example
xhttp.open("GET", "demo_get2.asp?fname=Henry&lname=Ford");
xhttp.send();
Try it Yourself »
How the server uses the input and how the server responds to a request, is explained in a later chapter.
POST Requests
A simple POST request:
Example
xhttp.open("POST", "demo_post.asp");
xhttp.send();
Try it Yourself »
To POST data like an HTML form, add an HTTP header with setRequestHeader().
Specify the data you want to send in the send() method:
Example
xhttp.open("POST", "ajax_test.asp");
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send("fname=Henry&lname=Ford");
Try it Yourself »
Method
Description
setRequestHeader(header, value)
Adds HTTP headers to the request
header: specifies the header name
value: specifies the header value
Synchronous Request
To execute a synchronous request, change the third parameter in the open() method to false:
xhttp.open("GET", "ajax_info.txt", false);
Sometimes async = false are used for quick testing. You will also find
synchronous requests in older JavaScript code.
Since the code will wait for server completion, there is no need for an onreadystatechange
function:
Example
xhttp.open("GET", "ajax_info.txt", false);
xhttp.send();
document.getElementById("demo").innerHTML = xhttp.responseText;
Try it Yourself »
Synchronous XMLHttpRequest (async = false) is not recommended because the JavaScript will
stop executing until the server response is ready. If the server is busy or slow, the
application will hang or stop.
Modern developer tools are encouraged to warn about using
synchronous requests and may throw an InvalidAccessError exception when it occurs.
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Reference: https://www.w3schools.com/js/js_ajax_http_send.asp